[android-developers] Re: How do I append an Xml File?

Ok, I'll start... and post the results.

Thank you.

Em quinta-feira, 30 de agosto de 2012 16h42min36s UTC-3, Guilherme Bernardi escreveu:

Hi.

I'm trying to append an Xml Data File.

The structure of Xml is:

<?xml version='1.0' encoding='UTF-8' standalone='yes' ?>

<clientes>

<cliente4>

    <Empresa>1</Empresa>

    <Codigo>5</Codigo>

    <Nome>gsdf</Nome>

    <Endereco>ags</Endereco>

    <Bairro>gasd</Bairro>

</cliente4>

</clientes>

I need to add another record. I got it, but the new record was inserted like this:

<?xml version='1.0' encoding='UTF-8' standalone='yes' ?>

<clientes>

<cliente4>

    <Empresa>1</Empresa>

    <Codigo>5</Codigo>

    <Nome>gsdf</Nome>

    <Endereco>ags</Endereco>

    <Bairro>gasd</Bairro>

</cliente4>

</clientes><cliente6><TESTE>testando</TESTE></cliente6><cliente6><TESTE>testando</TESTE></cliente6><cliente6><TESTE>testando</TESTE></cliente6>

How can I get the position of </cliente4> and append the new record or can I delete the EndTag </clientes> and add the new record and set the EndTag again?

To appending the file I'm using:

OutputStream is = openFileOutput("cliente.xml", MODE_APPEND);

            XmlSerializer serializer = Xml.newSerializer();

            serializer.setOutput(is, "UTF-8");

            serializer.startTag(null, "cliente6");

                serializer.startTag(null, "TESTE");

    serializer.text("testando");

    serializer.endTag(null, "TESTE");

            serializer.endTag(null,"cliente6");

            serializer.endDocument();

            serializer.flush();

            is.close();

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