try include commons-httpclient in your classpath (http://hc.apache.org/
downloads.cgi)
On Apr 30, 11:54 am, shaun <shashepp...@gmail.com> wrote:
> I found this bit of code. Not put it to use yet, but looks good to
> go. The "data" object is the byte[] representing the image.
>
> PostMethod method;
> try {
> HttpClient client = new HttpClient();
>
> client.getHttpConnectionManager().getParams().setConnectionTimeout(
> 5000);
> method = new PostMethod(urlString);
>
> Part[] parts = {
> new FilePart("videoFile", new
> ByteArrayPartSource(
> "videoFile",
> data)),
> new StringPart("videoName",
> filename) };
> method.setRequestEntity(new
> MultipartRequestEntity(parts, method
> .getParams()));
> client.executeMethod(method);
> response = method.getResponseBodyAsString();
> method.releaseConnection();
> } catch (Exception ex) {
> Log.v(TAG, "Exception", ex);
> } finally {
> method.releaseConnection();
> }
>
> On Apr 29, 3:25 am, Amit <prabhudesai.a...@gmail.com> wrote:
>
>
>
>
>
> > Hi,
>
> > I am a newbie to Android development; and I want to upload an image
> > (NOT an image file on the device, but a frame from a camera preview)
> > to a web-server. I searched around and got a snippet of code that can
> > be used to upload a byte array. This is the code:
>
> > public void uploadImage(final byte[] data) {
> > // spawn off a new thread to do the image uploading
> > new Thread(new Runnable() {
>
> > @Override
> > public void run() {
> > // TODO Auto-generated method stub
> > Log.d(TAG, "onRun:");
> > HttpURLConnection conn = null;
> > try {
> > serverURL = new URL(URL);
> > } catch (MalformedURLException e) {
> > // TODO Auto-generated catch block
> > Log.e(TAG, "Malformed URL!");
> > e.printStackTrace();
> > }
> > try {
> > // open up a connection with the server
> > conn = (HttpURLConnection) serverURL.openConnection();
>
> > // set up the conection
> > conn.setDoInput(true);
> > conn.setDoOutput(true);
> > conn.setUseCaches(true);
> > conn.setRequestMethod("POST");
> > conn.setRequestProperty("Connection", "Keep-Alive");
>
> > // now transfer the byte-stream
> > DataOutputStream ostream = new
> > DataOutputStream(conn.getOutputStream());
> > ostream.write(data);
> > ostream.flush();
> > ostream.close();
>
> > } catch (IOException e) {
> > // TODO Auto-generated catch block
> > Log.e(TAG, "No response from server!");
> > e.printStackTrace();
> > } finally {
> > conn.disconnect();
> > }
>
> > // wait for server response
> > try {
> > BufferedReader reader = new BufferedReader(
> > new InputStreamReader(conn.getInputStream())
> > );
> > String response;
> > while ((response = reader.readLine()) != null ) {
> > Log.d("server response: ", response);
> > }
> > reader.close();
> > } catch (IOException e) {
> > // TODO Auto-generated catch block
> > e.printStackTrace();
> > }
>
> > }
>
> > }).start();
> > }
>
> > First, is this code right, or am I missing something here?
>
> > Next, I want to know how can I simultaneously upload image AND
> > optional image tags to the server?
> > I got to the level that I need to send a multi-part request, but can't
> > seem to figure out the specifics. Can someone help me?
>
> > Also are there some 'best practices' to follow while doing this (like
> > for responsiveness, etc)?
>
> > Any help is much appreciated!
>
> > Thanks,
> > Amit
>
> > PS: Although this may be a little out-of-bounds for this forum, but
> > I'm also writing the server -- any help/ pointers on how to write it
> > to handle this POST request that the client sends? Got to write the
> > server in ASP.NET
> > Thanks again,
> > amit
>
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